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Popular >

foci (x-2)^2=2y+1

Solution

foci

(x - 2)^{2} = 2 y + 1

Solution

(2, 0)

Solution steps

Rewrite

(x - 2)^{2} = 2 y + 1

in the standard form:

4 \cdot \frac{1}{2} (y - (- \frac{1}{2})) = (x - 2)^{2}

(h, k) = (2, - \frac{1}{2}), p = \frac{1}{2}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(2, - \frac{1}{2})

along the y-axis

(2, - \frac{1}{2} + p)

= (2, - \frac{1}{2} + \frac{1}{2})

Refine

(2, 0)

Popular Examples

foci x=3-5(y+1)^2 foci

x = 3 - 5 (y + 1)^{2}

foci y=x^2-6x+11 foci

y = x^{2} - 6 x + 11

foci y=(x+1)^2+1 foci

y = (x + 1)^{2} + 1

foci-3(x+1)^2-1 foci

- 3 (x + 1)^{2} - 1

foci-16x+y^2+2y-63=0 foci

- 16 x + y^{2} + 2 y - 63 = 0

Frequently Asked Questions (FAQ)

What is the foci (x-2)^2=2y+1 ?
The foci (x-2)^2=2y+1 is (2,0)