What is the foci y=(18x^6)/(27x^4) ?

The foci y=(18x^6)/(27x^4) is (0, 3/8)

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foci y=(18x^6)/(27x^4)

foci

y = \frac{18 x ^{6}}{27 x ^{4}}

(0, \frac{3}{8})

Solution steps

Rewrite

y = \frac{18 x ^{6}}{27 x ^{4}}

in the standard form

4 \cdot \frac{3}{8} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{3}{8}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + \frac{3}{8})

Refine

(0, \frac{3}{8})

y^{2} - 2 y - 8 x - 39 = 0

- 2 x^{2} + 20 x - y - 52 = 0

(\frac{x - 5}{8})^{2} - (\frac{y + 2}{7}) = 1

5 x^{2}

x^{2} + 20 y = 0