What is the foci y^2-2y-8x-39=0 ?

The foci y^2-2y-8x-39=0 is (-3,1)

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foci y^2-2y-8x-39=0

foci

y^{2} - 2 y - 8 x - 39 = 0

(- 3, 1)

Solution steps

Rewrite

y^{2} - 2 y - 8 x - 39 = 0

in the standard form

4 \cdot 2 (x - (- 5)) = (y - 1)^{2}

(h, k) = (- 5, 1), p = 2

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(- 5, 1)

along the x-axis

(- 5 + p, 1)

= (- 5 + 2, 1)

Refine

(- 3, 1)

- 2 x^{2} + 20 x - y - 52 = 0

(\frac{x - 5}{8})^{2} - (\frac{y + 2}{7}) = 1

5 x^{2}

x^{2} + 20 y = 0

- 0.3 x^{2} + 2 x + 3