What are the solutions to the equation solvefor y,36x^2-25y^2+144x-50y+119=0 ?

The solutions to the equation solvefor y,36x^2-25y^2+144x-50y+119=0 are y=-(6x+17)/5 ,y=-(-6x-7)/5

Find the zeros of solvefor y,36x^2-25y^2+144x-50y+119=0

The zeros of solvefor y,36x^2-25y^2+144x-50y+119=0 are y=-(6x+17)/5 ,y=-(-6x-7)/5

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solve for

y, 36 x^{2} - 25 y^{2} + 144 x - 50 y + 119 = 0

y = - \frac{6 x + 17}{5}, y = - \frac{- 6 x - 7}{5}

Solution steps

36 x^{2} - 25 y^{2} + 144 x - 50 y + 119 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 25 y^{2} - 50 y + 36 x^{2} + 144 x + 119 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 50 ) \pm ( - 50 ) ^{2} - 4 ( - 25 ) ( 36 x ^{2} + 144 x + 119 )}{2 ( - 25 )}

Simplify

(- 50)^{2} - 4 (- 25) (36 x^{2} + 144 x + 119) : 60 (x + 2)

y_{1, 2} = \frac{- ( - 50 ) \pm 60 ( x + 2 )}{2 ( - 25 )}

Separate the solutions

y_{1} = \frac{- ( - 50 ) + 60 ( x + 2 )}{2 ( - 25 )}, y_{2} = \frac{- ( - 50 ) - 60 ( x + 2 )}{2 ( - 25 )}

y = \frac{- ( - 50 ) + 60 ( x + 2 )}{2 ( - 25 )} : - \frac{6 x + 17}{5}

y = \frac{- ( - 50 ) - 60 ( x + 2 )}{2 ( - 25 )} : - \frac{- 6 x - 7}{5}

The solutions to the quadratic equation are:

y = - \frac{6 x + 17}{5}, y = - \frac{- 6 x - 7}{5}

\frac{x ^{2}}{100} - \frac{y ^{2}}{64} = 1

x^{2} + y^{2} \leq 4

f (x) = x^{2} + 4 x + 3

y = \frac{1}{12} x^{2}

x^{2} + y^{2} - 6 x + 5 = 0

What are the solutions to the equation solvefor y,36x^2-25y^2+144x-50y+119=0 ?
The solutions to the equation solvefor y,36x^2-25y^2+144x-50y+119=0 are y=-(6x+17)/5 ,y=-(-6x-7)/5
Find the zeros of solvefor y,36x^2-25y^2+144x-50y+119=0
The zeros of solvefor y,36x^2-25y^2+144x-50y+119=0 are y=-(6x+17)/5 ,y=-(-6x-7)/5