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Popular >

foci x^2-8x+2y+7=0

Solution

foci

x^{2} - 8 x + 2 y + 7 = 0

Solution

(4, 4)

Solution steps

Rewrite

x^{2} - 8 x + 2 y + 7 = 0

in the standard form

4 (- \frac{1}{2}) (y - \frac{9}{2}) = (x - 4)^{2}

(h, k) = (4, \frac{9}{2}), p = - \frac{1}{2}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(4, \frac{9}{2})

along the y-axis

(4, \frac{9}{2} + p)

= (4, \frac{9}{2} + (- \frac{1}{2}))

Refine

(4, 4)

Popular Examples

foci x^2-4x-7 foci

x^{2} - 4 x - 7

foci y=2x^2+28x+105 foci

y = 2 x^{2} + 28 x + 105

foci (y-2)^2=2x+1 foci

(y - 2)^{2} = 2 x + 1

foci x^2-4x+3 foci

x^{2} - 4 x + 3

foci (x-4)^2=-12(y-3)foci

(x - 4)^{2} = - 12 (y - 3)

Frequently Asked Questions (FAQ)

What is the foci x^2-8x+2y+7=0 ?
The foci x^2-8x+2y+7=0 is (4,4)