What is the directrix (6x)/7*(4x)/3 ?

The directrix (6x)/7*(4x)/3 is y=-7/32

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directrix (6x)/7*(4x)/3

directrix

\frac{6 x}{7} \cdot \frac{4 x}{3}

y = - \frac{7}{32}

Solution steps

Rewrite

y = \frac{6 x}{7} \cdot \frac{4 x}{3}

in the standard form

4 \cdot \frac{7}{32} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{7}{32}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{7}{32}

Refine

y = - \frac{7}{32}

9 y^{2} - 6 y - 9 - x = 0

2 X^{2}

x^{2} + 3 x - 4

y = x^{2} - 4 x + 4

5 x (2 x + 4) - 3 x