What is the directrix y=-((x+3)^2)/(20)+1 ?

The directrix y=-((x+3)^2)/(20)+1 is y=6

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directrix y=-((x+3)^2)/(20)+1

directrix

y = - \frac{( x + 3 ) ^{2}}{20} + 1

y = 6

Solution steps

Rewrite

y = - \frac{( x + 3 ) ^{2}}{20} + 1

in the standard form:

4 (- 5) (y - 1) = (x - (- 3))^{2}

(h, k) = (- 3, 1), p = - 5

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- 3, 1)

y-coordinate

y = 1 - p

y = 1 - (- 5)

Refine

y = 6

x^{2} - 6 x + 10

y = 4 x^{2} + 2 x + 4

y = 2 x^{2} - 3 x

2 x^{2} - 2

2 x^{2} + 3

What is the directrix y=-((x+3)^2)/(20)+1 ?
The directrix y=-((x+3)^2)/(20)+1 is y=6