What is the directrix-4(y-10)=(x-6)^2 ?

The directrix-4(y-10)=(x-6)^2 is y=11

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directrix-4(y-10)=(x-6)^2

directrix

- 4 (y - 10) = (x - 6)^{2}

y = 11

Solution steps

Rewrite

- 4 (y - 10) = (x - 6)^{2}

in the standard form:

4 (- 1) (y - 10) = (x - 6)^{2}

(h, k) = (6, 10), p = - 1

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(6, 10)

y-coordinate

y = 10 - p

y = 10 - (- 1)

Refine

y = 11

4 - 7 x^{2}

3 x^{2} - x - 4

y = x^{2} - 10 x - 4

y = - 3 x^{2}

y = 3.1 + 6.6 x - 2.3 x^{2}