What is the directrix-x^2 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

directrix-x^2

directrix

- x^{2}

y = \frac{1}{4}

Solution steps

Rewrite

y = - x^{2}

in the standard form:

4 (- \frac{1}{4}) (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = - \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - (- \frac{1}{4})

Refine

y = \frac{1}{4}

x = - 8 y^{2}

y = 4 x^{2} + 23 x - 6

4 - X^{2}

x^{2} + 4 x - 4 y = 0

\frac{1}{2} (x^{2} - 4 x + 2)