What is the directrix y=5x^2 ?

The directrix y=5x^2 is y=-1/20

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directrix y=5x^2

directrix

y = 5 x^{2}

y = - \frac{1}{20}

Solution steps

Rewrite

y = 5 x^{2}

in the standard form:

4 \cdot \frac{1}{20} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{20}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{1}{20}

Refine

y = - \frac{1}{20}

3 x^{2} - x + 5

x^{2} + 6 y = 0

y = 2 x^{2} - 19 x + 9

- 2 x^{2}

\frac{x ^{5} + x ^{4} + x ^{3} + x ^{2} + x + 1}{x ^{3} + 1}