What is the foci x^2+(y^2)/(49)=1 ?

The foci x^2+(y^2)/(49)=1 is (0,4sqrt(3)),(0,-4sqrt(3))

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foci x^2+(y^2)/(49)=1

foci

x^{2} + \frac{y ^{2}}{49} = 1

(0, 43), (0, - 43)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

x^{2} + \frac{y ^{2}}{49} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 7, a = 1

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 7^{2} - 1^{2} : 43

(0, 0 + 43), (0, 0 - 43)

Refine

(0, 43), (0, - 43)

\frac{x ^{2}}{4} - \frac{y ^{2}}{25} = 1

y^{2} = 16 x

\frac{x ^{2}}{16} - \frac{y ^{2}}{25} = 1

\frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1

\frac{x ^{2}}{7} - \frac{y ^{2}}{2} = 1

What is the foci x^2+(y^2)/(49)=1 ?
The foci x^2+(y^2)/(49)=1 is (0,4sqrt(3)),(0,-4sqrt(3))