What is (x^2)/4-(y^2)/(25)=1 ?

The solution to (x^2)/4-(y^2)/(25)=1 is Hyperbola with (h,k)=(0,0),a=2,b=5

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(x^2)/4-(y^2)/(25)=1

\frac{x ^{2}}{4} - \frac{y ^{2}}{25} = 1

(h, k) = (0, 0), a = 2, b = 5

Solution steps

\frac{x ^{2}}{4} - \frac{y ^{2}}{25} = 1

Rewrite

\frac{x ^{2}}{4} - \frac{y ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} - \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 5

y^{2} = 16 x

\frac{x ^{2}}{16} - \frac{y ^{2}}{25} = 1

\frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1

\frac{x ^{2}}{7} - \frac{y ^{2}}{2} = 1

x^{2} + y^{2} + 12 x - 12 y + 36 = 0

What is (x^2)/4-(y^2)/(25)=1 ?
The solution to (x^2)/4-(y^2)/(25)=1 is Hyperbola with (h,k)=(0,0),a=2,b=5