What is x^2+y^2+12x-12y+36=0 ?

The solution to x^2+y^2+12x-12y+36=0 is Circle with (a,b)=(-6,6),r=6

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x^2+y^2+12x-12y+36=0

x^{2} + y^{2} + 12 x - 12 y + 36 = 0

(a, b) = (- 6, 6), r = 6

Solution steps

x^{2} + y^{2} + 12 x - 12 y + 36 = 0

Rewrite

x^{2} + y^{2} + 12 x - 12 y + 36 = 0

in the form of the standard circle equation

(x - (- 6))^{2} + (y - 6)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 6, 6), r = 6

x^{2} + y^{2} = 18

\frac{y ^{2}}{64} - \frac{x ^{2}}{9} = 1

x^{2} - 12 y - 6 x + 5 = 0

x^{2} + y^{2} = 64

x^{2} = - 36 y

What is x^2+y^2+12x-12y+36=0 ?
The solution to x^2+y^2+12x-12y+36=0 is Circle with (a,b)=(-6,6),r=6