What is the directrix y=x^2+4x+4 ?

The directrix y=x^2+4x+4 is y=-1/4

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directrix y=x^2+4x+4

directrix

y = x^{2} + 4 x + 4

y = - \frac{1}{4}

Solution steps

Rewrite

y = x^{2} + 4 x + 4

in the standard form

4 \cdot \frac{1}{4} (y - 0) = (x - (- 2))^{2}

(h, k) = (- 2, 0), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- 2, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{1}{4}

Refine

y = - \frac{1}{4}

y = - x^{2} + 5

y = - x^{2} + 10 x

y = x^{2} + 3

y = x^{2} + 1

y = x^{2} + x - 1