What is the directrix 4y^2-48x-20y=71 ?

The directrix 4y^2-48x-20y=71 is x=-5

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directrix 4y^2-48x-20y=71

directrix

4 y^{2} - 48 x - 20 y = 71

x = - 5

Solution steps

Rewrite

4 y^{2} - 48 x - 20 y = 71

in the standard form

4 \cdot 3 (x - (- 2)) = (y - \frac{5}{2})^{2}

(h, k) = (- 2, \frac{5}{2}), p = 3

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(- 2, \frac{5}{2})

x-coordinate

x = - 2 - p

x = - 2 - 3

Refine

x = - 5

y = (2 x + 5)^{2}

y = (x - 4)^{2} + 2

4 t - 9 t^{2}

y = (x + 2)^{2} - 3

- 2 x^{2} + 12 x - 2