What is the foci (y^2}{64}-\frac{x^2)/9 =1 ?

The foci (y^2}{64}-\frac{x^2)/9 =1 is (0,sqrt(73)),(0,-sqrt(73))

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foci (y^2}{64}-\frac{x^2)/9 =1

foci

\frac{y ^{2}}{64} - \frac{x ^{2}}{9} = 1

(0, 73), (0, - 73)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{64} - \frac{x ^{2}}{9} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 8, b = 3

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 8^{2} + 3^{2} : 73

(0, 0 + 73), (0, 0 - 73)

Refine

(0, 73), (0, - 73)

x^{2} - 12 y - 6 x + 5 = 0

x^{2} + y^{2} = 64

x^{2} = - 36 y

y^{2} = 20 x

x^{2} + 8 y = 0

What is the foci (y^2}{64}-\frac{x^2)/9 =1 ?
The foci (y^2}{64}-\frac{x^2)/9 =1 is (0,sqrt(73)),(0,-sqrt(73))