What is the directrix x= 1/4 y^2 ?

The directrix x= 1/4 y^2 is x=-1

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directrix x= 1/4 y^2

directrix

x = \frac{1}{4} y^{2}

x = - 1

Solution steps

Rewrite

x = \frac{1}{4} y^{2}

in the standard form:

4 \cdot 1 \cdot (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = 1

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - 1

Refine

x = - 1

y = - 3 (x + 2)^{2} + 5

y = 7 x^{2} - 3

- 0.0000005 x^{2} + 0.012 x + 19.21

4 y^{2} + x - 32 y + 68 = 0

y^{2} - 12 x = 0