What is the directrix-0.0000005x^2+0.012x+19.21 ?

The directrix-0.0000005x^2+0.012x+19.21 is y=500000

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directrix-0.0000005x^2+0.012x+19.21

directrix

- 0.0000005 x^{2} + 0.012 x + 19.21

y = 500000

Solution steps

Rewrite

y = - 0.0000005 x^{2} + 0.012 x + 19.21

in the standard form

4 (- 500000) (y - 0) = (x - \frac{0.012}{0.000001})^{2}

(h, k) = (\frac{0.012}{0.000001}, 0), p = - 500000

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(\frac{0.012}{0.000001}, 0)

y-coordinate

y = 0 - p

y = 0 - (- 500000)

Refine

y = 500000

4 y^{2} + x - 32 y + 68 = 0

y^{2} - 12 x = 0

3 - 2 x - x^{2}

x^{2} - 16

- 0.0001 x^{2} + 6.4 x + 7600

What is the directrix-0.0000005x^2+0.012x+19.21 ?
The directrix-0.0000005x^2+0.012x+19.21 is y=500000