What is the directrix-0.0001x^2+6.4x+7600 ?

The directrix-0.0001x^2+6.4x+7600 is y=2500

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directrix-0.0001x^2+6.4x+7600

directrix

- 0.0001 x^{2} + 6.4 x + 7600

y = 2500

Solution steps

Rewrite

y = - 0.0001 x^{2} + 6.4 x + 7600

in the standard form

4 (- 2500) (y - 0) = (x - \frac{6.4}{0.0002})^{2}

(h, k) = (\frac{6.4}{0.0002}, 0), p = - 2500

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(\frac{6.4}{0.0002}, 0)

y-coordinate

y = 0 - p

y = 0 - (- 2500)

Refine

y = 2500

x^{2} = 6 y

x = 3 y^{2}

y = x^{2} + 4 x - 1

y^{2} - 10 y - 12 x + 37 = 0

\frac{x}{25} - y^{2} = 1

What is the directrix-0.0001x^2+6.4x+7600 ?
The directrix-0.0001x^2+6.4x+7600 is y=2500