What is the directrix y=(6x)/7 (4x)/3 ?

The directrix y=(6x)/7 (4x)/3 is y=-7/32

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directrix y=(6x)/7 (4x)/3

directrix

y = \frac{6 x}{7} \frac{4 x}{3}

y = - \frac{7}{32}

Solution steps

Rewrite

y = \frac{6 x}{7} \cdot \frac{4 x}{3}

in the standard form

4 \cdot \frac{7}{32} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{7}{32}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{7}{32}

Refine

y = - \frac{7}{32}

\frac{4 x ^{3} + 11 x ^{2} + 4 x + 21}{x + 3}

- \frac{1}{3} (x - 3) = (y + 5)^{2}

+ 2.5 t^{2} + 6 t

y = x^{2} + 6 x + 8

- 5 t^{2} + 20 t

What is the directrix y=(6x)/7 (4x)/3 ?
The directrix y=(6x)/7 (4x)/3 is y=-7/32