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Popular >

foci x=-5y^2

Solution

foci

x = - 5 y^{2}

Solution

(- \frac{1}{20}, 0)

Solution steps

Rewrite

x = - 5 y^{2}

in the standard form:

4 (- \frac{1}{20}) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - \frac{1}{20}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + (- \frac{1}{20}), 0)

Refine

(- \frac{1}{20}, 0)

Popular Examples

eccentricity 9x^2+16y^2-72x+64y-368=0 eccentricity

9 x^{2} + 16 y^{2} - 72 x + 64 y - 368 = 0

y^{2} = - 16 x

foci y^2=-16x foci

y^{2} = - 16 x

asymptotes of (x^2)/9-(y^2)/4 =1 asymptotes

\frac{x ^{2}}{9} - \frac{y ^{2}}{4} = 1

vertices f(x)=-3x^2+12x-8 vertices

f (x) = - 3 x^{2} + 12 x - 8

Frequently Asked Questions (FAQ)

What is the foci x=-5y^2 ?
The foci x=-5y^2 is (-1/20 ,0)