What is the directrix y=x^2-10x+25 ?

The directrix y=x^2-10x+25 is y=-1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

directrix y=x^2-10x+25

directrix

y = x^{2} - 10 x + 25

y = - \frac{1}{4}

Solution steps

Rewrite

y = x^{2} - 10 x + 25

in the standard form

4 \cdot \frac{1}{4} (y - 0) = (x - 5)^{2}

(h, k) = (5, 0), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(5, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{1}{4}

Refine

y = - \frac{1}{4}

y = x^{2} + 10 x - 96

4 (x + 2)^{2} + 5

9 y^{2} + 12 x = 0

2 y^{2} - 16 y + 72 = 20 x

\frac{1}{2} x^{2}