What is the directrix 2x=(y-3)^2+4 ?

The directrix 2x=(y-3)^2+4 is x= 3/2

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directrix 2x=(y-3)^2+4

directrix

2 x = (y - 3)^{2} + 4

x = \frac{3}{2}

Solution steps

Rewrite

2 x = (y - 3)^{2} + 4

in the standard form:

4 \cdot \frac{1}{2} (x - 2) = (y - 3)^{2}

(h, k) = (2, 3), p = \frac{1}{2}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(2, 3)

x-coordinate

x = 2 - p

x = 2 - \frac{1}{2}

Refine

x = \frac{3}{2}

y = \frac{x ^{2}}{28} - \frac{5 x}{14} + \frac{333}{28}

y = 3 x^{2} + x - 1

y = x^{2} - 5 x + 6

y = x^{2} - 5 x + 3

(x - 1)^{2} = 4 (y - 1)