What is the directrix x=-1/4 y^2 ?

The directrix x=-1/4 y^2 is x=1

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directrix x=-1/4 y^2

directrix

x = - \frac{1}{4} y^{2}

x = 1

Solution steps

Rewrite

x = - \frac{1}{4} y^{2}

in the standard form:

4 (- 1) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - 1

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- 1)

Refine

x = 1

5 x + 3 y^{2} = 0

+ (x - 1)^{2} + 2

3 - 4 x^{2}

2 y^{2} - 5 y + x - 4 = 0

x^{2} + 2 x - 8