What is the directrix y^2-16x=0 ?

The directrix y^2-16x=0 is x=-4

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directrix y^2-16x=0

directrix

y^{2} - 16 x = 0

x = - 4

Solution steps

Rewrite

y^{2} - 16 x = 0

in the standard form:

4 \cdot 4 (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = 4

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - 4

Refine

x = - 4

2 x^{2} - 8 x + 9

- 2 x^{2} + 64 x - 90

y = \frac{x ^{2} - 4 x - 1}{7}

y^{2} - 28 x = 0

3 y^{2} = - 4 x