What is the directrix 2y^2-16x=0 ?

The directrix 2y^2-16x=0 is x=-2

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directrix 2y^2-16x=0

directrix

2 y^{2} - 16 x = 0

x = - 2

Solution steps

Rewrite

2 y^{2} - 16 x = 0

in the standard form:

4 \cdot 2 (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = 2

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - 2

Refine

x = - 2

(x + 2)^{2} - 4

y = \frac{1}{4} (x + 5)^{2} - 1

y = + (x + 6)^{2}

y = - 0.5 x^{2} - 3

4 x^{2} + 48 y + 12 x = 159