What is the directrix x^2+20y=10 ?

The directrix x^2+20y=10 is y= 11/2

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directrix x^2+20y=10

directrix

x^{2} + 20 y = 10

y = \frac{11}{2}

Solution steps

Rewrite

x^{2} + 20 y = 10

in the standard form:

4 (- 5) (y - \frac{1}{2}) = (x - 0)^{2}

(h, k) = (0, \frac{1}{2}), p = - 5

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, \frac{1}{2})

y-coordinate

y = \frac{1}{2} - p

y = \frac{1}{2} - (- 5)

Refine

y = \frac{11}{2}

2 y^{2} = - 3 x

x^{2} + 8 x + 7

(y + 5)^{2} = 6 (x + 1)

2 x^{2} + 5

2 y^{2} - 44 x = 0