What is the directrix 2y^2=-3x ?

The directrix 2y^2=-3x is x= 3/8

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directrix 2y^2=-3x

directrix

2 y^{2} = - 3 x

x = \frac{3}{8}

Solution steps

Rewrite

2 y^{2} = - 3 x

in the standard form:

4 (- \frac{3}{8}) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - \frac{3}{8}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- \frac{3}{8})

Refine

x = \frac{3}{8}

x^{2} + 8 x + 7

(y + 5)^{2} = 6 (x + 1)

2 x^{2} + 5

2 y^{2} - 44 x = 0

x = - \frac{3}{8} (y - 2)^{2} - 1