What is the directrix x=-3/8 (y-2)^2-1 ?

The directrix x=-3/8 (y-2)^2-1 is x=-1/3

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directrix x=-3/8 (y-2)^2-1

directrix

x = - \frac{3}{8} (y - 2)^{2} - 1

x = - \frac{1}{3}

Solution steps

Rewrite

x = - \frac{3}{8} (y - 2)^{2} - 1

in the standard form:

4 (- \frac{2}{3}) (x - (- 1)) = (y - 2)^{2}

(h, k) = (- 1, 2), p = - \frac{2}{3}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(- 1, 2)

x-coordinate

x = - 1 - p

x = - 1 - (- \frac{2}{3})

Refine

x = - \frac{1}{3}

(y + 12)^{2} = 9 (x - 9)

0.5 x^{2} + 2

y = - 2 + x^{2}

y^{2} + 4 x + 1 = 0

5 x^{2} - 13 x - 6

What is the directrix x=-3/8 (y-2)^2-1 ?
The directrix x=-3/8 (y-2)^2-1 is x=-1/3