What is the directrix y=-2+x^2 ?

The directrix y=-2+x^2 is y=-9/4

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directrix y=-2+x^2

directrix

y = - 2 + x^{2}

y = - \frac{9}{4}

Solution steps

Rewrite

y = - 2 + x^{2}

in the standard form:

4 \cdot \frac{1}{4} (y - (- 2)) = (x - 0)^{2}

(h, k) = (0, - 2), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, - 2)

y-coordinate

y = - 2 - p

y = - 2 - \frac{1}{4}

Refine

y = - \frac{9}{4}

y^{2} + 4 x + 1 = 0

5 x^{2} - 13 x - 6

x^{2} - 4 x - 5

4 x^{2} + 12 x + 9

5 x^{2}