What is the directrix 5x^2 ?

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directrix 5x^2

directrix

5 x^{2}

y = - \frac{1}{20}

Solution steps

Rewrite

y = 5 x^{2}

in the standard form:

4 \cdot \frac{1}{20} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{20}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{1}{20}

Refine

y = - \frac{1}{20}

x^{2} + x - 1

y^{2} - 8 x + 2 y + 17 = 0

6 (x - 8)^{2} + 7

y^{2} + 12 x + 8 y - 44 = 0

290 (8 x + 0.5 x^{2} - 1.4)