What is the directrix y^2-8x+2y+17=0 ?

The directrix y^2-8x+2y+17=0 is x=0

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directrix y^2-8x+2y+17=0

directrix

y^{2} - 8 x + 2 y + 17 = 0

x = 0

Solution steps

Rewrite

y^{2} - 8 x + 2 y + 17 = 0

in the standard form

4 \cdot 2 (x - 2) = (y - (- 1))^{2}

(h, k) = (2, - 1), p = 2

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(2, - 1)

x-coordinate

x = 2 - p

x = 2 - 2

Refine

x = 0

6 (x - 8)^{2} + 7

y^{2} + 12 x + 8 y - 44 = 0

290 (8 x + 0.5 x^{2} - 1.4)

x^{2} - x

+ 4 x^{2} - 4 x + 9