What is the directrix log_{10}(6)x^2 ?

The directrix log_{10}(6)x^2 is y=-1/(4log_{10)(6)}

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directrix log_{10}(6)x^2

directrix

lo g_{10} (6) x^{2}

y = - \frac{1}{4 lo g _{10} ( 6 )}

Solution steps

Rewrite

y = lo g_{10} (6) x^{2}

in the standard form:

4 \cdot \frac{1}{4 lo g _{10} ( 6 )} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{4 lo g _{10} ( 6 )}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{1}{4 lo g _{10} ( 6 )}

Refine

y = - \frac{1}{4 lo g _{10} ( 6 )}

y = \frac{1}{14} x^{2} + 2

x^{2} - 4 x + 4

6 x^{2} + 12 x

3 x^{2} + 18

(x - 2)^{2} = - 12 (y - 4)

What is the directrix log_{10}(6)x^2 ?
The directrix log_{10}(6)x^2 is y=-1/(4log_{10)(6)}