What is the directrix 3x^2+18 ?

The directrix 3x^2+18 is y= 215/12

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directrix 3x^2+18

directrix

3 x^{2} + 18

y = \frac{215}{12}

Solution steps

Rewrite

y = 3 x^{2} + 18

in the standard form:

4 \cdot \frac{1}{12} (y - 18) = (x - 0)^{2}

(h, k) = (0, 18), p = \frac{1}{12}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 18)

y-coordinate

y = 18 - p

y = 18 - \frac{1}{12}

Refine

y = \frac{215}{12}

(x - 2)^{2} = - 12 (y - 4)

\frac{5 t ^{2}}{2}

y = x^{2} - 2 x^{1}

x^{2} - 2 x

20 y = (x - 12)^{2} - 20