What is the directrix y=x^2-2x^1 ?

The directrix y=x^2-2x^1 is y=-5/4

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directrix y=x^2-2x^1

directrix

y = x^{2} - 2 x^{1}

y = - \frac{5}{4}

Solution steps

Rewrite

y = x^{2} - 2 x^{1}

in the standard form

4 \cdot \frac{1}{4} (y - (- 1)) = (x - 1)^{2}

(h, k) = (1, - 1), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(1, - 1)

y-coordinate

y = - 1 - p

y = - 1 - \frac{1}{4}

Refine

y = - \frac{5}{4}

x^{2} - 2 x

20 y = (x - 12)^{2} - 20

- 3 x^{2}

x^{2} - 8 x + 24

y = (x - 1)^{2} + 3