What is the directrix 3y^2=10x ?

The directrix 3y^2=10x is x=-5/6

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directrix 3y^2=10x

directrix

3 y^{2} = 10 x

x = - \frac{5}{6}

Solution steps

Rewrite

3 y^{2} = 10 x

in the standard form:

4 \cdot \frac{5}{6} (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = \frac{5}{6}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - \frac{5}{6}

Refine

x = - \frac{5}{6}

4 x^{2} - 5 x + 6

3 x^{2} + x - 5

(y - 0)^{2} = - 4 \cdot 0.01 (x - 0)

3 x^{2} - 10 x + 3

2 y^{2} + 8 x = 0