What is the directrix y^2-12x-2y-25=0 ?

The directrix y^2-12x-2y-25=0 is x=-31/6

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directrix y^2-12x-2y-25=0

directrix

y^{2} - 12 x - 2 y - 25 = 0

x = - \frac{31}{6}

Solution steps

Rewrite

y^{2} - 12 x - 2 y - 25 = 0

in the standard form

4 \cdot 3 (x - (- \frac{13}{6})) = (y - 1)^{2}

(h, k) = (- \frac{13}{6}, 1), p = 3

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(- \frac{13}{6}, 1)

x-coordinate

x = - \frac{13}{6} - p

x = - \frac{13}{6} - 3

Refine

x = - \frac{31}{6}

y = \frac{1}{4} (x - 1)^{2} - 2

25 x^{2} - 10 x - 200 y - 119 = 0

(y - 2)^{2} = - x - 3

2 x^{2} (2 + 1)

y = x^{2} + 16 x + 64

What is the directrix y^2-12x-2y-25=0 ?
The directrix y^2-12x-2y-25=0 is x=-31/6