What is the directrix 18x^2-64x-14y+150=0 ?

The directrix 18x^2-64x-14y+150=0 is y= 1627/252

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directrix 18x^2-64x-14y+150=0

directrix

18 x^{2} - 64 x - 14 y + 150 = 0

y = \frac{1627}{252}

Solution steps

Rewrite

18 x^{2} - 64 x - 14 y + 150 = 0

in the standard form

4 \cdot \frac{7}{36} (y - \frac{419}{63}) = (x - \frac{16}{9})^{2}

(h, k) = (\frac{16}{9}, \frac{419}{63}), p = \frac{7}{36}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(\frac{16}{9}, \frac{419}{63})

y-coordinate

y = \frac{419}{63} - p

y = \frac{419}{63} - \frac{7}{36}

Refine

y = \frac{1627}{252}

2 x^{2} + 5 x

y = - \frac{1}{14} x^{2} + 2

2 y^{2} = 16 x

y^{2} + 8 x + 2 y + 33 = 0

2 x^{2} - x + 1

What is the directrix 18x^2-64x-14y+150=0 ?
The directrix 18x^2-64x-14y+150=0 is y= 1627/252