What is the directrix 2y^2=16x ?

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directrix 2y^2=16x

directrix

2 y^{2} = 16 x

x = - 2

Solution steps

Rewrite

2 y^{2} = 16 x

in the standard form:

4 \cdot 2 (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = 2

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - 2

Refine

x = - 2

y^{2} + 8 x + 2 y + 33 = 0

2 x^{2} - x + 1

y^{2} = x

20 x = y^{2}

(x + 5)^{2} = 3 (y - 3)