What is the directrix 8(x-2)=(y+3)^2 ?

The directrix 8(x-2)=(y+3)^2 is x=0

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directrix 8(x-2)=(y+3)^2

directrix

8 (x - 2) = (y + 3)^{2}

x = 0

Solution steps

Rewrite

8 (x - 2) = (y + 3)^{2}

in the standard form:

4 \cdot 2 (x - 2) = (y - (- 3))^{2}

(h, k) = (2, - 3), p = 2

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(2, - 3)

x-coordinate

x = 2 - p

x = 2 - 2

Refine

x = 0

- x^{2} - 4 x - 4

y = x^{2} - 8 x

- x^{2} - 4 x + 2

y = x^{2} - 6 x

y^{2} + 4 x = 0