What is the directrix y=64x^2 ?

The directrix y=64x^2 is y=-1/256

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directrix y=64x^2

directrix

y = 64 x^{2}

y = - \frac{1}{256}

Solution steps

Rewrite

y = 64 x^{2}

in the standard form:

4 \cdot \frac{1}{256} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{256}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{1}{256}

Refine

y = - \frac{1}{256}

x^{2} + 2 x - 1 - (2 x^{2} - 3 x + 6)

\frac{1}{8} x^{2}

x^{2} + 8 x - 4 y - 36 = 0

\frac{1}{400} x^{2} - x + 150

y = (x - 1) (3 x + 1)