What is the directrix (y+6)^2= 15/11 (x+12) ?

The directrix (y+6)^2= 15/11 (x+12) is x=-543/44

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

directrix (y+6)^2= 15/11 (x+12)

directrix

(y + 6)^{2} = \frac{15}{11} (x + 12)

x = - \frac{543}{44}

Solution steps

Rewrite

(y + 6)^{2} = \frac{15}{11} (x + 12)

in the standard form:

4 \cdot \frac{15}{44} (x - (- 12)) = (y - (- 6))^{2}

(h, k) = (- 12, - 6), p = \frac{15}{44}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(- 12, - 6)

x-coordinate

x = - 12 - p

x = - 12 - \frac{15}{44}

Refine

x = - \frac{543}{44}

(y + 6)^{2} = 9 (x - 1)

y^{2} + 10 x = 0

y = - \frac{1}{2} (x + 6)^{2} + 8

(y - 3)^{2} = 2 (x + 2)

y = 5 x^{2} + 1

What is the directrix (y+6)^2= 15/11 (x+12) ?
The directrix (y+6)^2= 15/11 (x+12) is x=-543/44