What is the directrix y^2+10x=0 ?

The directrix y^2+10x=0 is x= 5/2

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directrix y^2+10x=0

directrix

y^{2} + 10 x = 0

x = \frac{5}{2}

Solution steps

Rewrite

y^{2} + 10 x = 0

in the standard form:

4 (- \frac{5}{2}) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - \frac{5}{2}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- \frac{5}{2})

Refine

x = \frac{5}{2}

y = - \frac{1}{2} (x + 6)^{2} + 8

(y - 3)^{2} = 2 (x + 2)

y = 5 x^{2} + 1

y = x^{2} + 9 x + 4

(x + 1)^{2} = 2 (y + 2)