What is the directrix 3x^2-6x+3 ?

The directrix 3x^2-6x+3 is y=-1/12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

directrix 3x^2-6x+3

directrix

3 x^{2} - 6 x + 3

y = - \frac{1}{12}

Solution steps

Rewrite

y = 3 x^{2} - 6 x + 3

in the standard form

4 \cdot \frac{1}{12} (y - 0) = (x - 1)^{2}

(h, k) = (1, 0), p = \frac{1}{12}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(1, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{1}{12}

Refine

y = - \frac{1}{12}

x = (y - 2) (3 y + 3)

\frac{1}{4} (x + 2)^{2} - 9

y^{2} - 12 x + 36 = 0

x^{2} - 6 x + 16

x^{2} - 6 x + 18