What is the directrix y^2-12x+36=0 ?

The directrix y^2-12x+36=0 is x=0

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directrix y^2-12x+36=0

directrix

y^{2} - 12 x + 36 = 0

x = 0

Solution steps

Rewrite

y^{2} - 12 x + 36 = 0

in the standard form:

4 \cdot 3 (x - 3) = (y - 0)^{2}

(h, k) = (3, 0), p = 3

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(3, 0)

x-coordinate

x = 3 - p

x = 3 - 3

Refine

x = 0

x^{2} - 6 x + 16

x^{2} - 6 x + 18

(x - 3)^{2} = - 12 (y - 2)

3 x^{2} - 5

\frac{4 x ^{3} - 7 x ^{2} - 11 x + 5}{4 x + 5}