What is the directrix (x-3)^2=-12(y-2) ?

The directrix (x-3)^2=-12(y-2) is y=5

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directrix (x-3)^2=-12(y-2)

directrix

(x - 3)^{2} = - 12 (y - 2)

y = 5

Solution steps

Rewrite

(x - 3)^{2} = - 12 (y - 2)

in the standard form:

4 (- 3) (y - 2) = (x - 3)^{2}

(h, k) = (3, 2), p = - 3

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(3, 2)

y-coordinate

y = 2 - p

y = 2 - (- 3)

Refine

y = 5

3 x^{2} - 5

\frac{4 x ^{3} - 7 x ^{2} - 11 x + 5}{4 x + 5}

(\frac{1}{2} - x) (- \frac{1}{2} - x)

y = - 8 x^{2}

3 x^{2} - x