What is the directrix-x^2+7 ?

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directrix-x^2+7

directrix

- x^{2} + 7

y = \frac{29}{4}

Solution steps

Rewrite

y = - x^{2} + 7

in the standard form:

4 (- \frac{1}{4}) (y - 7) = (x - 0)^{2}

(h, k) = (0, 7), p = - \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 7)

y-coordinate

y = 7 - p

y = 7 - (- \frac{1}{4})

Refine

y = \frac{29}{4}

y = - 16 x^{2} + 16 x + 480

- x^{2} + 5 x - 7

(x - 1)^{2} = 8 (y + 3)

+ 3 x^{2}

(x + 1)^{2} = 12 (y - 3)