What is the directrix 2y^2-12y-x+5=0 ?

The directrix 2y^2-12y-x+5=0 is x=-105/8

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directrix 2y^2-12y-x+5=0

directrix

2 y^{2} - 12 y - x + 5 = 0

x = - \frac{105}{8}

Solution steps

Rewrite

2 y^{2} - 12 y - x + 5 = 0

in the standard form

4 \cdot \frac{1}{8} (x - (- 13)) = (y - 3)^{2}

(h, k) = (- 13, 3), p = \frac{1}{8}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(- 13, 3)

x-coordinate

x = - 13 - p

x = - 13 - \frac{1}{8}

Refine

x = - \frac{105}{8}

- 0.03 x^{2} + 45 x + 124.5

- x^{2} - 4 x

4 y^{2} - 12 y + 56 x + 177 = 0

3 x^{2} + 19 x - 40

(y - 10)^{2} = - 12 (x + 2)