What is the directrix (y-10)^2=-12(x+2) ?

The directrix (y-10)^2=-12(x+2) is x=1

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directrix (y-10)^2=-12(x+2)

directrix

(y - 10)^{2} = - 12 (x + 2)

x = 1

Solution steps

Rewrite

(y - 10)^{2} = - 12 (x + 2)

in the standard form:

4 (- 3) (x - (- 2)) = (y - 10)^{2}

(h, k) = (- 2, 10), p = - 3

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(- 2, 10)

x-coordinate

x = - 2 - p

x = - 2 - (- 3)

Refine

x = 1

x^{2} + 4 x - 8 y + 12 = 0

x^{(2)} - 6 x + 5 y = - 34

12 (y - 2) = (x + 2)^{2}

x^{2} - 3 x - 4

(x - 4)^{2} = 8 (y + 2)

What is the directrix (y-10)^2=-12(x+2) ?
The directrix (y-10)^2=-12(x+2) is x=1