What is the directrix 12(y-2)=(x+2)^2 ?

The directrix 12(y-2)=(x+2)^2 is y=-1

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directrix 12(y-2)=(x+2)^2

directrix

12 (y - 2) = (x + 2)^{2}

y = - 1

Solution steps

Rewrite

12 (y - 2) = (x + 2)^{2}

in the standard form:

4 \cdot 3 (y - 2) = (x - (- 2))^{2}

(h, k) = (- 2, 2), p = 3

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- 2, 2)

y-coordinate

y = 2 - p

y = 2 - 3

Refine

y = - 1

x^{2} - 3 x - 4

(x - 4)^{2} = 8 (y + 2)

- \frac{1}{8} (y - 8)^{2} + 2

2 x^{2} - 10

y^{2} = 4 (- 4) x